暴力做法是对每个位置向右扫描找第一个更大值，O(n²)。可抽象为：元素像一排人，身高为数值。当前人「下一个更大」= 他右侧第一个没被挡住的人（比当前矮的都被挡住）。单调栈用 O(n) 维护「右侧候选更大值」：倒序遍历，弹掉 ≤ 当前的，栈顶即答案，再入栈当前值。
Explaining why customers further afield will be asked to recycle the bottles instead of returning them, Hartwig adds: "If the people purchasing them are from a different state, it's very unlikely they'll bring them back."
，这一点在搜狗输入法2026中也有详细论述
[qjoly@fedora]~% rpm-ostree status
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